Question on: WAEC Mathematics - 2004
If (y = 23_{five} + 101_{three}), find y, leaving your answer in base two
A
1110
B
10111
C
11101
D
111100
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Correct Option: B
(23_{five} = X_{ten}; X_{ten} = 2\times 5^1 + 3\times 5^0 = 10 + 3 = 13<br />
101_{three}=P_{ten}; P_{ten} = 1\times 3^2 + 0\times 3^1 + 1\times 3^0=9+0+1=10_{ten}<br />
Y = 13+10=23_{ten});
Converting to base two
(\begin{matrix}
2 & 23\
2 & 11 &R1\
2 & 5 & R1\
2 & 2 & R1\
2 & 1 & R0<br />
& 0& R1 \uparrow<br />
\end{matrix} <br />
=y=10111_2)
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